Interrupt Service Routines: Difference between revisions

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reworded one sentence, looks more sane now
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m (reworded one sentence, looks more sane now)
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====gcc / g++====
 
Neither gcc nor g++ offer any means (on x86 or x86-64) by which to have an interrupt service routine be only in C/ or C++ without performing '''black magic'''.
 
===Black Magic===
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